-10a^2+150=0

Solution for -10a^2+150=0 equation:

-10a^2+150=0

a = -10; b = 0; c = +150;
Δ = b2-4ac
Δ = 02-4·(-10)·150
Δ = 6000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6000}=\sqrt{400*15}=\sqrt{400}*\sqrt{15}=20\sqrt{15}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{15}}{2*-10}=\frac{0-20\sqrt{15}}{-20}
=-\frac{20\sqrt{15}}{-20}
=-\frac{\sqrt{15}}{-1}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{15}}{2*-10}=\frac{0+20\sqrt{15}}{-20}
=\frac{20\sqrt{15}}{-20}
=\frac{\sqrt{15}}{-1}
$